Intersoft Community - ClientUI - How to set the position and size of Window opened by UXDesktopDockButton

How to set the position and size of Window opened by UXDesktopDockButton

handy@intersoftpt.com — Tue, 06 Sep 2011 00:35:34 GMT

Hello,

Yes, I know. Normally, UXPage is always in Maximum size. Perhaps, you container which loads UXPage is not maximize.
E.g In our ClientUIDesktopApplication template, Welcome.xaml is a UXPage which load inside a window.
As default, it always show in full container. You can define the loaded window/container just from its window/container property. If you use window as its container, it surely has properties that I mentioned before.

But if it is purely UXPage itself, the position can be set WindowLeft and WindowTop properties.

Regards,
Handy

How to set the position and size of Window opened by UXDesktopDockButton

gavin — Mon, 05 Sep 2011 22:55:12 GMT

The window point to ApplicationUri is a uxpage,not a uxwindow,there is no WindowState and WindowStartupLocation property.

How to set the position and size of Window opened by UXDesktopDockButton

handy@intersoftpt.com — Mon, 05 Sep 2011 06:49:54 GMT

Hello,

You can specify its height and width in height/width property. To set maximize for window, simply change WindowState property to Maximize. Last about window startup position, you can configure the position in WindowStartupLocation property.

Regards,
Handy

How to set the position and size of Window opened by UXDesktopDockButton

gavin — Sun, 04 Sep 2011 21:51:53 GMT

When i use UXDesktopDockButton as below:

<Intersoft:UXDesktopDockButton Icon="/EpointFrame_SL;component/Assets/Images/Dock/todo.png"
Text="Mail" ApplicationUri="/Epoint.SL.DBMail;Epoint.SL.DBMail.Views.MailList" JumpingEffectHeight="20"/>

The window is opened when i click the button,but i can't set it's position and size. (It should be in maximize state,or in center position of the parent desktop. )

Can you tell me the solution.